Math, asked by ritesh5616, 3 months ago

A carpenter worked with to labour contracter and the daily wages he earned in four days with those contracter are given
Day contracter 1 contractor 2
1 ₹350 ₹330
2 ₹360 ₹390
3 ₹420 ₹410
4 ₹470 ₹470

a. calculate the average earning of the carpenter with both the contracter.
b. what does average represent ?
c. what is the range of daily wages with each contracter?




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Answers

Answered by satishwaghmare38350
0

Step-by-step explanation:

(a)

contractor 1 = 350 , 360 , 420, 470,

mean = sum of all observation / number of observation

mean = 350 + 360+ 420+ 470/ 4

=1600/4

=400

average= 400

contractor 2 =

330

₹390 , 410 ,470

mean = sum of all observation / number of observation

= 330 +390+410+470

1600/4

= 400

so , contractor 1 =400

contractor 2=400

(b)

carpenter earned same wages on both contractor

(c)

contractor 1 =350 , 360 , 420, 470,

range = highest value - lowest value

= 470 - 350

= 120

contractor 2 = 330 , ₹390 , 410 ,470

range = highest value - lowest value

= 470 - 330

= 140

Answered by Rameshjangid
0

Answer:

140

Step-by-step explanation:

Step 1: In statistics, in addition to the mode and median, the mean is one of the measures of central tendency. Simply said, the mean is the average of the values in the given collection. It indicates that values in a certain data collection are distributed equally. The three most often employed measures of central tendency are the mean, median, and mode. The total values provided in a datasheet must be added, and the sum must be divided by the total number of values in order to get the mean. When all of the values are organised in ascending order, the Median is the median value of the provided data. While the number in the list that is repeated a maximum of times is the mode.

Step 2: Contractor 1 = 350 , 360 , 420, 470,

mean = sum of all observation / number of observation

mean = 350 + 360+ 420+ 470/ 4

=1600/4

=400

average= 400

contractor 2 =

330

₹390 , 410 ,470

mean = sum of all observation / number of observation

= 330 +390+410+470

1600/4

= 400

so , contractor 1 =400

contractor 2=400

(b)Carpenter earned same wages on both contractor

(c)Contractor 1 =350 , 360 , 420, 470,

range = highest value - lowest value

= 470 - 350

= 120

contractor 2 = 330 , ₹390 , 410 ,470

range = highest value - lowest value

= 470 - 330

= 140

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