Question

A Carpenter works for five eight / nine hours on the first day and three five/twelve hours in the second day.How many hours did he work in two days

Answer 1

Answer:

Step-by-step explanation: Time taken to work in the first day= 5 8/9 hrs=5×9+8/9 (you have to divide the whole equation by 9) = 53/9 hrs

Time taken to work in the second day= 3 5/12 hrs= 3×12+5/12 (you have to divide the whole equation by 12)= 41/12

Total time taken= 53/9 + 41/12

Take the LCM of 9,12= 36 (In order to make the denominator same )

53/9 = 53×4/9×4= 212/36

41/12 = 41×3/12×3= 123/36

So, 53/9 + 41/12= 212/36 + 123/36 =335/36

Hope it helps.