A carpet is laid on the floor of a room 8 m by 5 m. There is a border of
constant width all around the carpet. If the area of the border is 12 m²,
find its width
de cach 5 m wide, running
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Answer:
Let the width of the border is 'x' m.
And
The length and breadth of the carpet are 8 m and 5 m
area of the carpet = 8m×5m = 40m²
length of the carpet without border = (8 – 2x)
breath of the carpet without border = (5–2x)
area of the border is 12m²
area of the carpet without border (8–2x)(5–2x)
Thus ,
12= 40– (8–2x)(5–2x)
==>12= 40-(40-26x +4x²)
==>12= 26x - 4x²
==>26x 4x²= 12
Then, ==>4x² – 26x +12= 0
==>2x²– 13x +6= 0
==>(2x - 1)(x-6) = 0
==>2x - 1= 0 and x - 6 = 0
==> x = 1/2 and x = 6
Because the border cannot be wider than the entire carpet, the width of the carpet is 1/2 m i.e., 50 cm.
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