Physics, asked by Nishi307, 1 year ago

A carrier wave of frequency 1.75 mhz, an amplitude 60v is modulated by a sinusoidal qave of frequency 12khz producing 60% amplitude modulation . Find out amplitude of the amplitude modulation wave.

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Answered by deepak2199
0
It has been found that any repeating, non-sinusoidal waveform can be equated to a combination of DC voltage, sine waves, and/or cosine waves (sine waves with a 90 degree phase shift) at various amplitudes and frequencies. This is true no matter how strange or convoluted the waveform in question may be. So long as it repeats itself regularly over time, it is reducible to this series of sinusoidal waves. In particular, it has been found that square waves are mathematically equivalent to the sum of a sine wave at that same frequency, plus an infinite series of odd-multiple frequency sine waves at diminishing amplitude:





This truth about waveforms at first may seem too strange to believe. However, if a square wave is actually an infinite series of sine wave harmonics added together, it stands to reason that we should be able to prove this by adding together several sine wave harmonics to produce a close approximation of a square wave. This reasoning is not only sound, but easily demonstrated with SPICE.

The circuit we’ll be simulating is nothing more than several sine wave AC voltage sources of the proper amplitudes and frequencies connected together in series. We’ll use SPICE to plot the voltage waveforms across successive additions of voltage sources, like this: (Figurebelow)



A square wave is approximated by the sum of harmonics.


In this particular SPICE simulation, I’ve summed the 1st, 3rd, 5th, 7th, and 9th harmonic voltage sources in series for a total of five AC voltage sources. The fundamental frequency is 50 Hz and each harmonic is, of course, an integer multiple of that frequency. The amplitude (voltage) figures are not random numbers; rather, they have been arrived at through the equations shown in the frequency series (the fraction 4/π multiplied by 1, 1/3, 1/5, 1/7, etc. for each of the increasing odd harmonics).

building a squarewave v1 1 0 sin (0 1.27324 50 0 0) 1st harmonic (50 Hz) v3 2 1 sin (0 424.413m 150 0 0) 3rd harmonic v5 3 2 sin (0 254.648m 250 0 0) 5th harmonic v7 4 3 sin (0 181.891m 350 0 0) 7th harmonic v9 5 4 sin (0 141.471m 450 0 0) 9th harmonic r1 5 0 10k .tran 1m 20m .plot tran v(1,0) Plot 1st harmonic .plot tran v(2,0) Plot 1st + 3rd harmonics .plot tran v(3,0) Plot 1st + 3rd + 5th harmonics .plot tran v(4,0) Plot 1st + 3rd + 5th + 7th harmonics .plot tran v(5,0) Plot 1st + . . . + 9th harmonics .end

I’ll narrate the analysis step by step from here, explaining what it is we’re looking at. In this first plot, we see the fundamental-frequency sine-wave of 50 Hz by itself. It is nothing but a pure sine shape, with no additional harmonic content. This is the kind of waveform produced by an ideal AC power source: (Figure below)



Pure 50 Hz sinewave.


Next, we see what happens when this clean and simple waveform is combined with the third harmonic (three times 50 Hz, or 150 Hz). Suddenly, it doesn’t look like a clean sine wave any more: (Figurebelow) mark as brainlist





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