a carrom board (4ft x 4ft square) has the queen at the center. the queen hit by the striker moves to the front edge, rebounce and goes in the hole behind the striking line. find the magnitude of displacement of the queen - 1) from the center to the front edge. (2) from the edge to the hole. (3) from the center to the hole
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Answer:
By law of reflection ∠i=∠r
or tani=tanr (from triangle OAB and BDC)
x
2−x
=
2
4
Or 4−2x=x
⇒3x=2⇒x=
3
2
We get BD=2−
3
2
=
3
4
(i) : Thus displacement of queen from front edge to hole
BC
=
3
2
i
^
+2
j
^
Magnitude of displacement ∣
OB
∣=
(
3
2
)
2
+2
2
=
3
2
10
ft
(ii) : Thus displacement of queen from center to front edge
BC
=
3
4
i
^
−4
j
^
Magnitude of displacement ∣
BC
∣=
(
3
4
)
2
+4
2
=
3
4
10
ft
(iii) : Thus displacement of queen from center to hole
OC
=2
i
^
−2
j
^
Magnitude of displacement ∣
OC
∣=
(2)
2
+2
2
=2
2
ft
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