Question

A cart acceleration from rest and acquies a speed of 36km /hr in 10sec.find 1.acceleration
2.total distance travelled
3.velocity at the end of 6th sec
4.the distance at the end of 6th sec

Answer 1

36km/hr = 36*5/18 = 10 m/s

1. Acceleration = (v - u)/t = (10 - 0)/10 = 1 m/s^2

2. Total distance travelled = 0.5at^2 = 0.5*1*(10)^2 = 50m

3. Velocity at the end of 6th sec = u + at = 0 + 1*6 = 6m/s

4. Distance at the end of 6th second = 0.5at^2 = 0.5*1*(6)^2 = 18m