A cart engine is pushed by a force of 200 kN in 50s, but the cart is not forwarded. How much work is done ?
Answers
Answered by
1
Answer:
The answer is 0 J
Explanation:
Given:
F = 200 kN = 0.2 N (force is in Newton. First convert the kN to N. How? Since 1 N is equal to 1000kN, and to convert kN to N we divide 200 kN to 1000 1Kn)
t = 50 sec
d = 0 (cart didn't move forward)
The formula is
W = (Fd)/t
Solution:
W = (0.2 N x 0)/50 s (substitute the given to the formula)
W = 0/50s
W = 0 J
No work is done in the problem.
Work exist if there is a movement. And since in the problem, the cart didn't even move therefore there is no Work done at all.
Answered by
0
Answer:
No work is done.
Explanation:
Since work done = Force applied × distance move in the direction of force.But here cart is not moving forward. So distance =0
Hence work done = 200kN ×0
= 0
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