Question

. A cart of mass 20 kg at rest is to be dragged at a
speed of 18 km - If the co-efficient of friction
between the cart and the ground is 0.1, what is
the minimum force required to drag the cart to a
distance of 10 m? (Take g = 10 m s 2)​

Answer 1

Given,

• Initial velocity(u) = 0 m/s
• Final velocity(v) = 18km/h = 5m/s

v² - u² = 2as

⇒ a = (v² - u²) /2s

⇒ a = (25-0) /2×10

⇒ a = 25/20

⇒ a = 1.25 m/s²

The minimum force required to drag the cart to the distance 10 m

F = mgu + ma

⇒ F = (0.1 × 20 × 10) + ( 20 × 1.25)

⇒ F = 20 + 25

⇒ F = 45 N

$\boxed{\bold{\therefore{Minimum\:Force = 45\:N}}}$