Question

A cart of mass 20 kg is moving with a velocity 5 m/sec on a straight track. a body of mass 5 kg falls vertically on the cart and both are moving together with a speed of m/sec.​

Answer 1

Answer:

We will use conservation of momentum

Let a body of mass M travelling with velocity u for length L. After each interval of length L mass

2

L

is added to the cart with the original body of mass M.

by adding all the time intervals for

2

9L

distance

t=t

1

+t

2

+t

3

+t

4

+t

5

=

2u

17L

.

Explanation:

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Answer 2

Explanation:

Let their velocities after the collision be v

1

and v

2

. As we know for elastic collision.

Relative velocity of approach = relative velocity of separation

10−4=v

2

−v

1

⇒6=v

2

−v

1

⇒v

1

=v

2

−6

Applying conservation of momentum,

10×10+5×4=10v

1

+5v

2

120=10v

1

+5v

2

120=10(v

2

−6)+5v

2

=15v

2

−60

15v

2

=180⇒v

2

=12cm/sec

v

1

=6cm/sec

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