Question

A cart of mass 20 kg is moving with a velocity 5 m/sec on a straight track. a body of mass 5 kg falls vertically on the cart and both are moving together with a speed of ........ m/sec.


Don't spam ​

Answer 1

Step-by-step explanation:

Let their velocities after the collision be v

1

and v

2

. As we know for elastic collision.

Relative velocity of approach = relative velocity of separation

10−4=v

2

−v

1

⇒6=v

2

−v

1

⇒v

1

=v

2

−6

Applying conservation of momentum,

10×10+5×4=10v

1

+5v

2

120=10v

1

+5v

2

120=10(v

2

−6)+5v

2

=15v

2

−60

15v

2

=180⇒v

2

=12cm/sec

v

1

=6cm/sec