A cart of mass 200kg is at rest on a horizontal frictionless surface. A man of mass 50kg is standing on the cart as shown in the figure. If the man starts running to right with speed 20km/h relative to cart then velocity of cart is
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Dear....
At rest linear momentum(mv)=0
So by conservation of linear momentum .....if man(50kg) starts towards right i.e. +i direction then total mass (cart+man)moves opposite to man(i.e. -i or left) to neutralize the resultant linear momentum.
Mathematically,
50×20i+(200+50)×4(-i) =0
Note- if cart moves then the man running on it also moves to left
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