Question

a cart of mass 500 kg is standing at rest on the rails. a man weighing 70 kg and running parallel to the railtrack with a velocity of 10 m/s jumps on to the cart on approaching it. find the velocity with which the cart will start moving

Answer 1

U can apply law of conservation of energy here.

Initial kinetic energy of cart=0.

Initial kinetic energy of man=1/2×mv^2

=1/2×70×(10)^2

Total initial energy= kinetic energy of cart.

Final total energy =1/2×(m+M)v^2

Where m is mass of man and M is mass of cart.

As they move with same velocity at the end, common velocity is v.

1/2×70×100=1/2×570×v^2

V^2=700/57

V=3.5m/s.

Answer 2

Answer:

1.4 m/s^2

Explanation:

m1v1= m2v2

500v1=70×10

V1= 1.4 m)s^2...

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