A cart of weight 25 N is released at the top of an inclined plane of length 1m, which makes an angle of 30° with the ground. It rolls down the plane and hits another cart of weight 40 N at the bottom of the incline. Calculate the speed of the first cart at the bottom of the incline and the speed at which both carts move together after the impact.
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a = g sin 30° = 4.9 m/s
v² = u²+ 2 a s = 0 + 2 * 4.9 * 1
v = √9.8 m/s
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both move at v.
conservation of momentum.
25 * √9.8 = (25+40) * v
find v.
v² = u²+ 2 a s = 0 + 2 * 4.9 * 1
v = √9.8 m/s
=============
both move at v.
conservation of momentum.
25 * √9.8 = (25+40) * v
find v.
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