A cart of weight 25 N is released at the top of an inclined plane of length 1m, which makes
an angle of 30° with the ground. It rolls down the plane and hits another cart of weight 40 N
at the bottom of the incline. Calculate the speed of the first cart
Answers
Answered by
0
W = 25 N
L = 1m
Ф = 30°
Height h of the plane = L Sin 30 = 1/2 m
KE = PE at the top
1/2 m v² = m g h
=> v = √(2 * 9.8 * 1/2) = √9.8 m/s
====================
if both carts travel together after collision:
25 * √9.8 = 65 * v => find v
L = 1m
Ф = 30°
Height h of the plane = L Sin 30 = 1/2 m
KE = PE at the top
1/2 m v² = m g h
=> v = √(2 * 9.8 * 1/2) = √9.8 m/s
====================
if both carts travel together after collision:
25 * √9.8 = 65 * v => find v
Similar questions