Question

A carton contains 9 brown, 6 red, 7 blue and 6 white eggs. Find the probability that an egg selected at random is:
(i) brown
(ii) white
(iii) red
(iv) blue.

Answer 1

Answer:

Step-by-step explanation:

Numbers of brown eggs = 8

Numbers of white eggs = 4

Total Number of eggs = 8 + 4 = 12

P(E)=\frac{Tota\ln umberoffavourableoutcomes}{Tota\ln umberofoutcomes}

(i) P (of getting a brown egg) = \frac{8}{12}=\frac{2}{3}

(ii) P (of getting a white egg) = \frac{4}{12}=\frac{1}{3}