a carton of 24 bulbs contain 6 defective bulbs one bulb is drawn at random what is the probability that the bulb is not defective if the bulb selected is defective and not replaced and if second bulb is selected at random from the rest what is the probability that the second one is defective
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There are 6 defective bulbs out of 24 bulbs
Favourable number of elementary events = 24 – 6 = 18
∴ Probability that the bulb is not defective =18/24=3/4
When the selected bulb is defective and not replaced,then
Total bulbs = 23, defective bulbs = 5
∴ Probability that the second bulb is defective =5/23
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