A cartoon of 24 bulb contain 6 defective bulbs , one bulb drawn at random . What is the probability that the bulb is not defective? if the bulb is not replaced and second bulb is selected at random from rest , what is the probability that the bulb is defective?
Answers
Answered by
58
Probability of getting non defective bulbs = 18/24
Probability of getting defective bulbs = 6/24
Probability of getting defective bulbs = 6/24
Answered by
37
P(e)=number of favourable outcome\total number of outcome
a)
=18/24 by dividing we get
=9/12
b)
=6/23
a)
=18/24 by dividing we get
=9/12
b)
=6/23
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