Question

A cas travels with speed of 30 km/hr and then return back with a speed of 50km/hr.Find average speed of the car.
Please answer i will mark u as brainleist​

Answer 1

Given :-

• car travelled with the seed of 30 km/hr
• return back to the speed of 50 km/hr

Solution :-

• Let, first position = A
• last position = B

• Let the distance from A to B be x.
• But the distance travelled is 2x.

Time taken by the car when it moves from A to B is given by

→ ${\bold{t1 \: =\: \frac{Distance}{Speed} \:= \: \frac{x}{30}}}$

Time taken by the car when it moves from B to A,

→ ${\bold{t2 \: =\: \frac{Distance}{Speed} \:= \: \frac{x}{50}}}$

• Total distance = 2x.

→ Total time :-

→ t1 + t2

→ ${\bold{ \frac{x}{30} \:+\: \frac{x}{50}}}$

→ ${\bold{ \frac{(5x+3x)}{150}}}$

→ ${\bold{\frac{8x}{150}}}$

So, Average speed =

→ ${\bold{\frac{Total\:distance}{total\: time}}}$

→ ${\bold{ \frac{2x}{8x/150}}}$

$\sf\huge\underline\pink{= \:37.5\:km/hr}$