a cask contains 65 litres of a mixture of milk and water mixed in the ratio of 10:3, how much water must be added to it so that the ratio of milk and water may be 8:5
Answers
Answer:
6 liters
Step-by-step explanation:
The required amount of water added is x=6 liter.
Step-by-step explanation:
Given : A cask contains a mixture of 49 liters of wine and water in the proportion 5:2.
To find : How much water must be added to it so that the ratio of wine to water may be 7:4 ?
Solution :
Total mixture = 49 liters
The ratio of wine and water is 5 : 2
Sum = 5+2=7
Total wine is W=49\times \frac{5}{7}=35W=49×
7
5
=35
Total water is w=49\times \frac{2}{7}=14w=49×
7
2
=14
Let x water liter should be added,
According to question,
35:14+x=7:435:14+x=7:4
\frac{35}{14+x}=\frac{7}{4}
14+x
35
=
4
7
Cross multiply,
35\times 4=7\times (14+x)35×4=7×(14+x)
140=98+7x140=98+7x
7x=140-987x=140−98
7x=427x=42
x=\frac{42}{7}x=
7
42
x=6x=6
Therefore, The required amount of water added is x=6 liter.
Answer:
your answer is in attachment
