a cat at rest accelerates uniformly to a speed of 144km/h in 20s.How much distance is covered by car
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velocity of car = 144km/hr=144000m/60×60sec=40m/s
distance = speed × time therefore distance=40×20=800m
distance = speed × time therefore distance=40×20=800m
yakshak8:
But at back side of book the answer is 1200m
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u=0m/s
v=144 X 1000/3600 =40m/s
t =20 s
v= u+at
40 =o+ aX20
a= 2m/s^2
Now, v^2 -u^2 =2as
40^2-0 =2X2Xs
1600=4s
s = 1600/4
s= 400m......
v=144 X 1000/3600 =40m/s
t =20 s
v= u+at
40 =o+ aX20
a= 2m/s^2
Now, v^2 -u^2 =2as
40^2-0 =2X2Xs
1600=4s
s = 1600/4
s= 400m......
Thanks but at back of book the answer is 1200m
The answer at the back needs not always to be correct....
You follow and revise the steps done by me and then crosscheck the answer with your teacher
yeah he is right i got wrong ... i cant edit in required time
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