a cat at rest accelerates uniformly to a speed of 144km/h in 20s.How much distance is covered by car
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velocity of car = 144km/hr=144000m/60×60sec=40m/s
distance = speed × time therefore distance=40×20=800m
distance = speed × time therefore distance=40×20=800m
yakshak8:
But at back side of book the answer is 1200m
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u=0m/s
v=144 X 1000/3600 =40m/s
t =20 s
v= u+at
40 =o+ aX20
a= 2m/s^2
Now, v^2 -u^2 =2as
40^2-0 =2X2Xs
1600=4s
s = 1600/4
s= 400m......
v=144 X 1000/3600 =40m/s
t =20 s
v= u+at
40 =o+ aX20
a= 2m/s^2
Now, v^2 -u^2 =2as
40^2-0 =2X2Xs
1600=4s
s = 1600/4
s= 400m......
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