A catalyst lowers the activation energy for a certain reaction from 83.314 to 75 kj mol1 at 500 k. What will be the rate of reaction as compared to uncatalysed reaction? Assume other things being equal.
Answers
Answered by
14
Answer:
The rate of reaction will increases by 0.135 times.
Explanation:
According to the Arrhenius equation,
The expression used with catalyst and without catalyst is,
where,
= rate of reaction with catalyst
= rate of reaction without catalyst
= activation energy with catalyst = 75 kJ/mol =75000 J/mol
= activation energy without catalyst = 83.314 kJ/mol = 83,314 J/mol
R = gas constant = 8.314 J/mol K
T = temperature =
Now put all the given values in this formula, we get
Therefore, the rate of reaction will increases by 0.135 times.
Similar questions