Question

A catapult fires a stone of mass 0.04 kg vertically upwards. If the stone has
an initial kinetic energy of 48 J, how high will it travel before it starts to fall
back to the ground?
14​

Answer 1

Answer:

Here, k.E = P.E

48 = mgh

h = 48/ 0.04 × 10

h = 120 m

Answer 2

Answer:

120m

Explanation:

h=K.E/m x 10

h=48/0.04 x 10

h=120m