Physics, asked by dhruvasodariya1010, 8 months ago

A catapult on an aircraft carrier is capable of accelerating a plane from 0 ms1 to 40 ms-1 over a distance of 80 m. Find the average net force that the catapult exerts on a 13300 kg jet.

Answers

Answered by pastimeplays
3

Answer:

133000 N

Explanation:

First we need to find the acceleration on the plane.

u = 0 m/s

v = 40 m/s

s = 80 m

Using the second equation of motion,

v² - u² = 2as

40² - 0² = 2a(80)

1600 = 160a

a = 10 m/s²

m = 13300 kg

F = ma

F = 13300 x 10 N

  = 133000 N

Answered by TheEmeraldBoyy
104

{\huge{\boxed{\sf{\green{❥✰Question✰}}}}}

A catapult on an aircraft carrier is capable of accelerating a plane from 0 ms1 to 40 ms-1 over a distance of 80 m. Find the average net force that the catapult exerts on a 13300 kg jet.

{\huge{\underline{\bf{\pink{❥✰➵ANSWER :-✰}}}}}

Required Solution...

{\bigstar \:{\pmb{\sf{\underline{About \: question...}}}}}★

⋆ Understanding the question: This question says that we have to find out the average net force that the catapult exerts on a 13300 kilograms jet. Given that there is a catapult on an aircraft and it is capable of accelerating a plane from 0 to 56 m/s in a distance of 80 m. Let's do it!

{\bigstar \:{\pmb{\sf{\underline{Provided \: that...}}}}}★

\begin{gathered}\sf According \: to \: statement \begin{cases} & \sf{Initial \: velocity \: = \bf{0 \: m/s}} \\ \\ & \sf{Final \: velocity \: = \bf{56 \: m/s}} \\ \\ & \sf{Distance \: = \bf{80 \: metres}} \\ \\ & \sf{Mass \: of \: body \: = \bf{13300 \: kilograms}} \\ \\ & \sf{Average \: net \: force \: = \bf{?}} \end{cases}\\ \\\end{gathered} ⎪⎪⎪⎪⎪⎪⎪⎪⎪⎧

According to Statement

Initialvelocity=0m/s

Finalvelocity=56m/s

Distance=80metres

Massofbody=13300kilograms

Averagenetforce=?

{\bigstar \:{\pmb{\sf{\underline{Using \: concepts...}}}}}★

⋆ Third equation of motion is given by the mentioned formula:

{\small{\underline{\boxed{\sf{2as \: = v^2 - u^2}}}}} 2as=v 2 −u 2

(Where, a denotes acceleration , s denotes displacement or distance , v denotes final velocity and u denotes initial velocity)

⋆ Newton's second law of motion formula that is of force is given by:

{\small{\underline{\boxed{\sf{F \: = ma}}}}} F=ma

(Where, F denotes force , m denotes mass of body and a denotes acceleration)

{\bigstar \:{\pmb{\sf{\underline{Full \; Solution...}}}}}★

~ Firstly by using third equation of motion let us find out the acceleration!

\begin{gathered}:\implies \sf 2as \: = v^2 - u^2 \\ \\ :\implies \sf 2a(80) = (56)^{2} - 0^{2} \\ \\ :\implies \sf 2a(80) = 3136 - 0 \\ \\ :\implies \sf 2(a)(80) = 3136 \\ \\ :\implies \sf 2(80a) = 3136 \\ \\ :\implies \sf 160a = 3136 \\ \\ :\implies \sf a = 3136/160 \\ \\ :\implies \sf a = 19.6 \: ms^{-2}\end{gathered} :⟹2as=v 2 −u 2 :⟹2a(80)=(56) 2 −0 2

:⟹2a(80)=3136−0

:⟹2(a)(80)=3136

:⟹2(80a)=3136

:⟹160a=3136

:⟹a=3136/160

:⟹a=19.6ms

−2

Henceforth, we get 19.6 m/s sq. as the acceleration.

~ Now by using Newton's second law of motion formula that is of force, let us solve the whole question!

\begin{gathered}:\implies \sf F \: = ma \\ \\ :\implies \sf F \: = 13300(19.6) \\ \\ :\implies \sf F \: = 13300 \times 19.6 \\ \\ :\implies \sf F \: = 260680.0 \: Newton \\ \\ :\implies \sf Average \: net \: force \: = 260.68 \: kN\end{gathered}

Henceforth, we get 260.68 kN as average net force.

{\large{\pmb{\sf{\underline{AdditioNal \: Knowledge...}}}}}

➟ Newton's law of motion -Newton if the father of physics and he established the laws of motion in his book named ❛Principia❜ in the year 1667.

➟ Newton's first law of motion - Every body maintain it's maintain it's initial state of rest or motion with uniform speed on straight line unless an external force act on it.

◆ It's also known to be law of Galileo or law of inertia.

• Law of inertia = It is the property of a body by virtue of which the body opposes change in it's initial state of rest or motion with uniform speed on a straight line. There are 2 types of inertia –

⑴ Inertia of rest

⑵ Inertia of motion

Some examples of inertia –

⑴ When a coat /blanket is beaten by a stick the dust particles are removed.

⑵ When a car start suddenly the passenger bends backwards.

◆ Important - First law gives the definition of force.

• Force - It is that external cause which when acts on a body changes or tries to change the initial state of the body.

• Momentum - It is that property of a moving body and is defined of mass and velocity of the body. It's a vector quantity. SI unit is kgm/s.

\: \: \: \: \: \: \:{\sf{Momentum = \: Mass \times Velocity}} \: \: \green\starMomentum=Mass×Velocity⋆

➟ Newton's 2nd law of motion - The rate of change in momentum of a body is directly proportional to the applied force on the body and take place in the direction of force.

If f = force applied ; a = acceleration produced and m = mass of body the nF = ma.

◆ Newton's second law gives the magnitude of force.

◆ Newton's first law is contained in the second law.

➟ Newton's 3rd law of motion - To every action there is an equal and opposite reaction.

Some examples -

⑴ Motion of the rocket.

⑵ Recoil of the gun.

Thanks!

ITzEmeraldBoyy

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