Question

A catapult on an aircraft carrier is capable of accelerating a plane from 0 to 56 m/s in a distance of 80 m. Find the average net force that the catapult exerts on a 13300 kg jet.​

Answer 1

Answer:

Average net force exerted by the catapult will be 260680N.

Explanation:

According to the Question

It is given that

• Initial velocity ,u = 0m/s
• Final velocity ,v = 56m/s
• distance travelled ,s = 80m
• Mass of catapult ,m = 13300kg

we have to calculate the average net force that will be exerted by catapult .

Firstly we calculate the acceleration of the aircraft.

Using Kinematics Equation

• v² -u² = 2as

Substitute the value we get

➻ 56²-0² = 2*a*80

➻ 3136-0 = 160*a

➻ 3136 = 160*a

➻ a = 3136/160

➻ a = 19.6m/s²

So, the acceleration of the aircraft 19.6m/s².

Now, calculating the average force exerted by the catapult .

• F = ma

Substitute the value we get

➻ F = 13300*19.6

➻ F = 1330*196

➻ F = 260680N

• Hence, the average net force that catapult will exert 260680 Newton.

Answer 2

• initial velocity=u=0m/s
• Final velocity=v=56m/s
• Distance=s=80m
• Mass=m=13300kg
• Force=F=?

Using second equation of kinematics

$\boxed{\sf v^2-u^2=2as}$

• a denotes to acceleration

$\\ \sf\longmapsto a=\dfrac{v^2-u^2}{2s}$

$\\ \sf\longmapsto a=\dfrac{56^2-0^2}{2(80)}$

$\\ \sf\longmapsto a=\dfrac{3136}{160}$

$\\ \sf\longmapsto a=19.6m/s^2$

According to Newtons second law

$\boxed{\sf F=ma}$

$\\ \sf\longmapsto Force=13300\times 19.6$

$\\ \sf\longmapsto Force=260680N$