Question

A catapult on an aircraft carrier is capable of accelerating a plane from 0 to 56.0 ms^1 in a distance of 80.0 m.find the average net force that the catapult exerts on a 13 300 kg jet

The final answer is 2.61×10^5N

Answer 1

Given the initial velocity, the distance and the final velocity we can get the acceleration of the plane.

We will use the following kinematics equation :

V² = U² + 2as

V = 56

U = 0

S = 80

Doing the substitution we have :

56² = 0 + 2 × a × 80

3136 = 160a

a = 3136/160

a = 19.6 m/s²

= 19.6 m/s²

Force = mass × acceleration

Force = 13300 × 19.6 = 260680 N

= 2.60680 × 10⁵ N

Approximately :

2.61 × 10⁵ N

Answer 2

Answer:

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