Physics, asked by keshavprajapati6008, 11 months ago

A cause direct a horizontal jet of water moving with a velocity of 20 metre per second on a vertical wall the cross section area of the jet is 5 into 10 power minus 4 metre square if the density of water is 1000 kg metre cube calculate the force on the wall assuming the water is brought to rest there

Answers

Answered by pushsid

1

Answer:

Explanation:

It is 245

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