Physics, asked by Vaishnavikeshri8079, 7 months ago

A cavity of radius R/2 is made inside a solid sphere of
radius R. The centre of the cavity is located at a distance R/
2 from the centre of the sphere. The gravitational force on a
particle of mass ‘m’ at a distance R/2 from the centre of the
sphere on the line joining both the centres of sphere and
cavity is – (opposite to the centre of gravity)
[Here g = GM/R², where M is the mass of the sphere]
(a)mg/2
(b)3mg/8
(c)mg/16
(d) None of these

Answers

Answered by sauravsingh13956
0

Answer:

(a)mg/2 will be the answer I think so if it

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