Question

A ceiling of hall 50m high. What is maximum horizontal distance that ball thrown with speed 30m/s can go without hitting ceiling of hall??
​

Answer 1

Step-by-step explanation:

H

max

=

g

μ

2

sin

2

θ

=25m

=

9.8

(40)

2

×sin

2

θ

=25m

sin

2

θ =0.153125

θ=23

0

Now, T

g

2μsinθ

=

9.8

2×40×0.4

=3.19sec

Now, x = μcosθ×T

=40x cos(23

0

) x 3.19

x= 117.62 m

Therefore , maximum horizontal distance is 117.62 metres.

Please mark this Answer Brainlist