Question

A cell emf of 18V and internal resistance 1.5Ω is connected to an Ammeter of resistance 1Ω and resistor 2Ω.
Find the:
a) Ammeter reading
b) Terminal Voltage
(please show the steps too. I will mark correct answer as brainiest)

Answer 1

Answer:

Given

The emf of the cell =1.5V

Internal resistance (r) =0.5Ω

From graph we observe that

V=

⇒ resistance of the conductor (R) =

I

V

(∵ from ohm's law)

=1Ω

so the total resistance of the current path =R+r

=1+0.5Ω

=1.5Ω

From ohm's the current in the circuit (i) = total r

=

1.5

1.5

A

=1A

the voltage across the terminals =emf of cell−voltage drop across internal resistance

=emf−(i×r)

=1.5−(1×0.5)

=1.0V

Explanation:

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