Question

A cell has a potential difference of 6 V in an open circuit, but it falls to 4 V when a current of 2 A is drawn from it. Find the internal resistance of the cell.

Answer 1

Hello there!

If a cell has a potential difference of 6V in an open circuit, it means that the EMF of that cell is 6V.

Let's assume that the internal resistance of the cell is R ohms.

Thus if the potential difference of the cell falls to 4V from 6V then the remaining 2V is across the internal resistance of the cell.

Current through the circuit given in the question is 2A.

Hence we will find the internal resistance R, by the given formula:

V = I × R

2V = 2A × R

2 = 2×R

R = 1 ohms.

Hence the internal resistance of the cell, R is 1 ohms.

Answer 2

Answer:

if a cell has a potential difference of 6V in an open circuit, it means that the EMF of that cell is 6V.

Let's assume that the internal resistance of the cell is R ohms.

Thus if the potential difference of the cell falls to 4V from 6V then the remaining 2V is across the internal resistance of the cell.

Current through the circuit given in the question is 2A.

Hence we will find the internal resistance R, by the given formula:

V = I × R

2V = 2A × R

2 = 2×R

R = 1 ohms.

Hence the internal resistance of the cell, R is 1 ohms.

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