Question

A cell has an emf of 15V. When short circuited, it gives a
current of 3A. The internal resistance of the cell is
a) 3Ω b) 0.3 Ω c) 0.2 Ω d)5 Ω​

Answer 1

Answer:-

• Voltage=V=15V
• Current=I=3A
• Resistance=R=?

According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \sf\longmapsto Resistance=\dfrac{15}{3}$

$\\ \sf\longmapsto Resistance=5\Omega$

Option D is correct.

Answer 2

Answer:d)5 ohm

Explanation: r=£÷I

r=15÷3

r=5 ohm