Question

a cell has an emf of 5.0v and an internal resistance of 1.0ohm.it terminals are joined through a 9ohm resistor.calculate the current in the circuit and PD across the terminals of the cell

Answer 1

Answer:

Solution is attached herewith. Have a nice day. Please mark as brainliest

Answer 2

Given:

• Cell has EMF of 5 volts and internal resistance of 1 ohm.
• External resistance is 9 ohm.

To find:

• Current in circuit ?
• Potential difference across cell ?

Calculation:

First of all, let's find out the net resistance in circuit:

$R_{net} = R_{int} + R_{ext}$

$\implies R_{net} = 1 + 9$

$\implies R_{net} = 10 \: ohm$

So, current in circuit is :

$i = \dfrac{potential \: difference}{R_{net}}$

$\implies \: i = \dfrac{5}{10}$

$\implies \: i = 0.5 \: amp$

Now, potential difference across cell is :

$V = E - iR_{int}$

$\implies V = 5 - (0.5 \times 1)$

$\implies V = 5 - 0.5$

$\implies V = 4.5 \: volts$

Hope It Helps.