A cell is connected across two points on a uniform circular conductor. prove that the magnetic field at the centre
will be zero.
Answers
Answered by
4
As conductor is connected with the cell , the potential difference across two paths (two possible paths i.e. one upside and one downside path) is same.
V1 = V2
I1R1=I2R2
I1dl1=I2dl2 (as resistivity and area of cross section same )
Now,
field, due to one path, is opposite due to another part. So magnetic field at the center is

[sin 90 = 1 , i1dl1 = i2dl2]
= 0 (proved)
As conductor is connected with the cell , the potential difference across two paths (two possible paths i.e. one upside and one downside path) is same.
V1 = V2
I1R1=I2R2
I1dl1=I2dl2 (as resistivity and area of cross section same )
Now,
field, due to one path, is opposite due to another part. So magnetic field at the center is

[sin 90 = 1 , i1dl1 = i2dl2]
= 0 (proved)
V1 = V2
I1R1=I2R2
I1dl1=I2dl2 (as resistivity and area of cross section same )
Now,
field, due to one path, is opposite due to another part. So magnetic field at the center is

[sin 90 = 1 , i1dl1 = i2dl2]
= 0 (proved)
As conductor is connected with the cell , the potential difference across two paths (two possible paths i.e. one upside and one downside path) is same.
V1 = V2
I1R1=I2R2
I1dl1=I2dl2 (as resistivity and area of cross section same )
Now,
field, due to one path, is opposite due to another part. So magnetic field at the center is

[sin 90 = 1 , i1dl1 = i2dl2]
= 0 (proved)
Answered by
0
What that question it no no
Similar questions
Physics,
9 months ago
Social Sciences,
9 months ago
Business Studies,
1 year ago
Physics,
1 year ago