Question

A cell is connected to a 6 ohm resistance, because of which heat of 6000 J is produced per second due to current flowing through it. Obtain the potential difference applied across the resistance.​

Answer 1

Explanation:

For 3Ω resistance heat =

R

V

2

=12J

V

2

=12×R=36

V=

36

For upper branch in parallel combination

R

net

=6Ω,V=6V

i=

R

V

=

6

6

=1A

Heat produced in 4Ω

P=H=L

2

R=1

2

(4)=4J

Hence, the correct option is (B)

Answer 2

Answer:

Explanation:

Given: R = 9 Ω

H = 400 J

t = 1 s

To find: V = ?

Formula: H = V2

t

R

Solution: H = V2

t

R

400 = V2 × 1

9

3600 = V2

V = √ 3600

V = 60 V