Physics, asked by Anonymous, 4 months ago

A cell of 1.5 V is connected to an external resistance x, when current flowing through it is 0.24 A. Find the magnitude of resistance x.​

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Answered by csangita311
0

Answer:

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Answered by Anonymous
4

Given:

  • Current (I) = 0.24 A

  • Potential difference (V) = 1.5 V

To find:

Resistance (R)

Solution:

We know that,

R = V/I (by Ohm's law)

R = 1.5/0.24

= 150/24

= 50/8

= 6.25 Ω

Hence, resistance is 6.25 Ω.

Extra information:

What is Ohm's law?

Ohm's law states that the current flowing in a conductor is directly proportional to the potented difference across its ends provided the physical conductors and temperature of conductor remains constant.

The ratio of potential difference and current is commonly called resistance of a conductor. Then according to Ohm's law.

V/I = R

or

I = V/R

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