Question

A cell of 2.0 volt and negligible resistance is connected in an electrical circuit where 3 ohm and 9 ohm are connected in series and this combination is
connected with 2.75 ohm and the cell in series Calculate the current flowing through 3 ohm resistance​

Answer 1

Answer:

we know that in series combination the current is same across all resistors

so Req= 9+3=12 ohm

v = 2

I = v/r

I = 2/12

I = 1/6