Question

A cell of 6 v and internal resistance 2 is connected to a variable resistor. For what value of current does maximum power dissipation occur in the circuit

Answer 1

Answer:

formula used,

V=Ir

I=V/r

Explanation:

it is given that,

V=6v

r=2

now,

I=6/2

I=3A

Answer 2

Answer:

$18W$

Explanation:

Given that,

$V=6v\\\\R = 2ohm$

And,

Power Dissipated in a circuit

The equation of power is $P = V X I$

$P = I^2 R$ [ since$V = IR$]

$V$ is the voltage

$I$ is the current

$R$ is the resistance

the formula used for find I,

$V = IR\\\\I= V/R$

now,

$I=6/2\\\\\I=3A$

power is

$P = VX I\\\\= 6X3\\\\=18 W$