A cell of e.m.f. 1.5 V is connected with an ammeter of resistance of 0.05 Q. If the current in the circuit is 2.0A, the internal resistance of the cell is : [BSEB, 2010] (A) 1.0 12. (B) 0.9 12 (C) 0.8 2 0.7 Ω Ans. (D) Β)
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Answer:
1.5 ×0.05 ÷ 2.0 product
will be internal resistance p
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