A cell of e.m.f. 1.5V and internal resistance 2.0 ohms is connected in series with an ammeter of resistance 0.5 ohms and a 10 ohms resistor. Find the current in the circuit.
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Answer: If resistances are in series equivalent resistance= sum of individual resistances.
Here equivalent resistance say R =2+0.5+10 ohms
Now current in the circuit =V/R
Here V=1.5 volt
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