Question

A cell of e.m.f. 2 V and internal resistance 1.2 ohm is connected ta an ammeter of resistance 0.8 ohm and 2 resistors 4.5 ohm and 9 ohm as shown in figure.

Find :


(a) the reading of the ammeter,
(b)
the potential difference across the terminals of
the cell, and

(c) the potential difference across the 4.5 resistor.


​

Answer 1

1) current in 0.8ohm resistance,I=E/R+r=2/1.2+3.8=0.4A and 2)terminal voltage ,V=E-IR=2-0.4×1.2=2-0.48=1.52A

Answer 2

i hope ur dount is cleared