Question

A cell of e.m.f E and internal resistance 1·0 ohm is connected in series with resistors 2 ohm and 3 ohm . If the potential difference across the 3 ohm resistor is 1·5volts calculate the e.m.f of the cell with working?

Answer 1

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Answer 2

okk..
in the series .. r= r1+r2
so r= 5 ohm ..
it is given that the 1.5 volt works ... in 3 ohm resister then supplied current will be .. I =V/r

so I = 1.5 /3. = 0.5 amp

actually .... I used to be constant in series so
I will be constant..
then e= v+ ir .

e= 5×0.5+1×0.5
e= 2.5 +0.5. e= 3volt
then
emf of cell is 3 volt ..

mark it ..sir ..