Question

A cell of emf 1.5v is connected with an ammeter of resistance 0.05 ohm. If the current in circuit if of 0.2a, the internal resistance of the cell is

Answer 1

Hey mate I hope this helps you

Answer 2

Hello friend,

◆ Answer-

r = 7.45 ohm

◆ Explaination-

# Given-

EMF of cell E = 1.5 V

Resistance of ammeter R = 0.05 ohm

Current in circuit I = 0.2 A

# Solution-

We know the relation,

R + r = E/I

0.05 + r = 1.5/0.2

0.05 + r = 7.5

r = 7.5 - 0.05

r = 7.45 ohm

Therefore, internal resistance of the cell is 7.45 ohm.

Hope this helps...