Physics, asked by asthanaanjali, 11 months ago

A cell of emf 1.8V and Internal resistance 2 ohm is connected to an ammeter in series and a resistor of 4.5 ohm​

Answers

Answered by Anonymous
7

\Large\underline{\underline{\sf Given:}}

  • Emf (e) = 1.8V

  • Resistance (R') = 2Ω

  • Internal Resistance (r) = 4.5Ω

\Large\underline{\underline{\sf To\:Find:}}

  • Reading of Ammeter (I) = ?

\Large\underline{\underline{\sf Formula\:Used:}}

\large{\boxed{\sf I=\dfrac{Emf(e)}{Total\: Resistance (R)}}}

\Large\underline{\underline{\sf Solution:}}

Total Resistance (R) = R' + r

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀= 2 + 4.5

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 6.5 Ω

On Putting Value :

\implies{\sf I=\dfrac{1.8}{6.5}}

\implies{\sf I=0.27\:A }

\Large\underline{\underline{\sf Answer:}}

⛬ Reading of Ammeter is 0.27A

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