Question

a cell of emf 10v and internal resistance 2 ohm is connected across a resistance 8 ohm find the potential difference across battery do answers guyssss

Answer 1

Answer:

First we'll find the current in circuit from equivalent resistance of circuit

In upper and lower branch 1Ω and 3Ω are in series, their equivalent is 4Ω.

Now both 4Ω resistances are in parallel, their equivalent is 2Ω.  

2Ω and 3Ω are in series their equivalent is 5Ω.  

I=  10/5

​ =2A

current will be equally divided between both branches, current in each branch will be  

2 /2

​=1A

potential drop across 1Ω is 1×1=1 V

potential drop across 3Ω is 1×3=3 V

potential difference between between A and B is 3−1=2 V