A cell of emf 12v and internal resistance 0.1ohm is used in a circuit calculate potential difference between it's terminal when it is connected to resistance of 0.2ohm?
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Answer:
EMF of the cell(E) =2 V
internal resistance(r)= 0.1 V
External resistance(R)=3.9 V
V=IR
=(E÷(R+r))×R
=(2÷(3.9+0.1))×3.9
=1.95 V
Therefore potential difference across the terminals of the cell =
1.95V.
Explanation:
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