A cell of emf 2 volt and internal reestance of 1/3-2 ts connected to two resistances of 10-2 and 20-2 joined in paralled, find current throgh each resistance.
Answers
Answered by
0
Answer:
R
eq
=4+
10+24
10×24
=11.06Ω
I=
R
V
=
11.06
3
=0.27A
V
1
=V
2
I
1
R
1
=I
2
R
2
10I
1
=24I
2
I
1
=2.4I
2
I
1
+I
2
=3.4I
2
=0.27
Current through 24Ω =I
2
=0.08A
Current through 10Ω =I
1
=0.19A
Similar questions