Question

A cell of emf 3V & negligible internal resistance is connected to potentiometer wire of resistance 18Ω & length 4m. The potential gradient of wire is?​

Answer 1

Answer:

Current, I=$\frac{E}{R}$=$\frac{3}{18}$

Potential across the potentiometer wire is: $V_{P}$=10I=10*$\frac{3}{18}$

Potential gradient is: k= $\frac{V}{L}$$= \frac{10*3}{18*4}$

k=0.416

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