Question

A cell of emf 3v and internal resistance 4 ohm is connected to resistors 10 ohm and 24 ohm in paralllel, find current through each resistance

Answer 1

1/Re1=(1/R1)+(1/ R2)
=( 1/4)+(1/10)
=7/20
Re1= 20/7
I1=v/R=3/20/7=21/20=10.5
lly
Re2=24/7
I2=3/24/7=21/24=7/8=8.75

Answer 2

Concept:

Internal resistance is defined as the barrier to current flow supplied by the cells and batteries themselves, resulting in heat creation. 

Given:

e.m.f = 3V

$R_{1} = 10 ohm\\R_{2}= 24 ohm$

$r= 4ohm$

To Find:

Current through each resistance.

Solution:

Let $R_{eq} be the equivalent resistance.$

$\mathrm{R}_{\text {eq }}=4+\frac{10 \times 24}{10+24}=11.06 \Omega \\ \mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{3}{11.06}=0.27 \mathrm{~A} \\ \mathrm{~V}_{1}=\mathrm{V}_{2} \\ \mathrm{I}_{1} \mathrm{R}_{1}=\mathrm{I}_{2} \mathrm{R}_{2} \\ 10 \mathrm{I}_{1}=24 \mathrm{I}_{2} \\ \mathrm{I}_{1}=2.4 \mathrm{I}_{2} \\ \mathrm{I}_{1}+\mathrm{I}_{2}=3.4\mathrm{I}_{2}=0.27$

$I_{2} = \frac{0.27}{3.4} = 0.8 A\\I_{1} = 2.4 I_{2} = 0.19 A$

The current through each resistance is $0.8A and 0.19 A$ respectively.

                                                                                                          #SPJ2