Question

A cell of emf 4 volt and internal resistance 1 ohm is connected to a potentiometer wire of length 100 cm and resistance 9 ohm a cell of unknown emf is connected in the secondary circuit and the balancing length is found to be 50 cm the emf of the cell in the secondary circuit is

Answer 1

Explanation:

Let V be the potential across balance point and one end of wire.

Let V be the potential across balance point and one end of wire.Hence acccording to the principle of potentiometer

Let V be the potential across balance point and one end of wire.Hence acccording to the principle of potentiometer V∝l.

Let V be the potential across balance point and one end of wire.Hence acccording to the principle of potentiometer V∝l.Also if a cell of emf E is employed in the circuit between the ends of potentiometer wire of length L then

Let V be the potential across balance point and one end of wire.Hence acccording to the principle of potentiometer V∝l.Also if a cell of emf E is employed in the circuit between the ends of potentiometer wire of length L thenE∝L.