Question

A cell of emf 6v and internal resistance 0.5 ohm is joined I. parallel with another cell of 10 v and internal resistance 1 ohm the above combination sends a current through an external resistance 12 ohm find the current through each cell​

Answer 1

Explanation:

The potential difference between AB,CD and EF are same.

Applying Kirchhoff's law,

6−(0.5)I

1

=10−I

2

=12(I

1

+I

2

)

solving above equations, we get

I

1

=2.87A.

Hope it helps to u....

Please follow me ....